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8x^2+60x-68=0
a = 8; b = 60; c = -68;
Δ = b2-4ac
Δ = 602-4·8·(-68)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-76}{2*8}=\frac{-136}{16} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+76}{2*8}=\frac{16}{16} =1 $
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